Integrand size = 16, antiderivative size = 14 \[ \int \frac {\log \left (x^{-n} \left (a+x^n\right )\right )}{x} \, dx=\frac {\operatorname {PolyLog}\left (2,-a x^{-n}\right )}{n} \]
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Time = 0.01 (sec) , antiderivative size = 14, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.125, Rules used = {2511, 2438} \[ \int \frac {\log \left (x^{-n} \left (a+x^n\right )\right )}{x} \, dx=\frac {\operatorname {PolyLog}\left (2,-a x^{-n}\right )}{n} \]
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Rule 2438
Rule 2511
Rubi steps \begin{align*} \text {integral}& = \int \frac {\log \left (1+a x^{-n}\right )}{x} \, dx \\ & = \frac {\text {Li}_2\left (-a x^{-n}\right )}{n} \\ \end{align*}
Time = 0.01 (sec) , antiderivative size = 14, normalized size of antiderivative = 1.00 \[ \int \frac {\log \left (x^{-n} \left (a+x^n\right )\right )}{x} \, dx=\frac {\operatorname {PolyLog}\left (2,-a x^{-n}\right )}{n} \]
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Time = 2.16 (sec) , antiderivative size = 15, normalized size of antiderivative = 1.07
method | result | size |
derivativedivides | \(\frac {\operatorname {dilog}\left (1+a \,x^{-n}\right )}{n}\) | \(15\) |
default | \(\frac {\operatorname {dilog}\left (1+a \,x^{-n}\right )}{n}\) | \(15\) |
risch | \(-\ln \left (x \right ) \ln \left (x^{n}\right )+\frac {n \ln \left (x \right )^{2}}{2}+\frac {i \pi \ln \left (x \right ) \operatorname {csgn}\left (i x^{-n}\right ) \operatorname {csgn}\left (i x^{-n} \left (a +x^{n}\right )\right )^{2}}{2}+\frac {i \pi \ln \left (x \right ) \operatorname {csgn}\left (i \left (a +x^{n}\right )\right ) \operatorname {csgn}\left (i x^{-n} \left (a +x^{n}\right )\right )^{2}}{2}-\frac {i \pi \ln \left (x \right ) \operatorname {csgn}\left (i x^{-n} \left (a +x^{n}\right )\right )^{3}}{2}-\frac {i \pi \ln \left (x \right ) \operatorname {csgn}\left (i x^{-n}\right ) \operatorname {csgn}\left (i \left (a +x^{n}\right )\right ) \operatorname {csgn}\left (i x^{-n} \left (a +x^{n}\right )\right )}{2}+\frac {\ln \left (a +x^{n}\right ) \ln \left (-\frac {x^{n}}{a}\right )}{n}+\frac {\operatorname {dilog}\left (-\frac {x^{n}}{a}\right )}{n}\) | \(171\) |
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Leaf count of result is larger than twice the leaf count of optimal. 61 vs. \(2 (13) = 26\).
Time = 0.30 (sec) , antiderivative size = 61, normalized size of antiderivative = 4.36 \[ \int \frac {\log \left (x^{-n} \left (a+x^n\right )\right )}{x} \, dx=\frac {n^{2} \log \left (x\right )^{2} - 2 \, n \log \left (x\right ) \log \left (\frac {a + x^{n}}{a}\right ) + 2 \, n \log \left (x\right ) \log \left (\frac {a + x^{n}}{x^{n}}\right ) - 2 \, {\rm Li}_2\left (-\frac {a + x^{n}}{a} + 1\right )}{2 \, n} \]
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\[ \int \frac {\log \left (x^{-n} \left (a+x^n\right )\right )}{x} \, dx=\int \frac {\log {\left (a x^{- n} + 1 \right )}}{x}\, dx \]
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\[ \int \frac {\log \left (x^{-n} \left (a+x^n\right )\right )}{x} \, dx=\int { \frac {\log \left (\frac {a + x^{n}}{x^{n}}\right )}{x} \,d x } \]
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\[ \int \frac {\log \left (x^{-n} \left (a+x^n\right )\right )}{x} \, dx=\int { \frac {\log \left (\frac {a + x^{n}}{x^{n}}\right )}{x} \,d x } \]
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Timed out. \[ \int \frac {\log \left (x^{-n} \left (a+x^n\right )\right )}{x} \, dx=\int \frac {\ln \left (\frac {a+x^n}{x^n}\right )}{x} \,d x \]
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